Question

A potential difference of 27.0 V is measured across a 4.50 ✕ 10³ Ω resistor.

9. [-/10 Points] DETAILS SERCP10 21.WU.002. A potential difference of 27.0 Vis measured across a 4.50 x 1032 resistor. (a) Determine the current through the resistor. A (b) Determine the power dissipated by the resistor. w

Answer 1

We have the ohms law, V = IR

Where V is the voltage =27.0v

I is the current = ? V

R is the resistance of the resistor = 4.5*10³ Ohm

So subtituting the values,

27= I * 4.5*10³

I = 27/ (4.5*10³) = 6*10^-3 Ampere

So the current flowing through the resistor =

6*10^-3 A

b. We have the equation of power dissipation by a resistor , P= I²R = (6*10-³)²* 4.5*10³

P= 0.162 Watts

So the power dessipated = 0.162 W

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