ANSWER:
In E2 elimination reaction, both leaving group halide and neighboring hydrogen should be in antiperiplanar i.e. angle between both should 180o. So, one option is there to go forward reaction is to attack at less substituted hydrogen here. That's why here we are getting less substituted alkene as product.
d Both elimination reaction. Experimental evidence shows that this reaction produces the less-substituted alkene as the...
53) What alkene is formed in greatest yield in the following Hofmann elimination? он CH3 CH3 CH 3CH2CH2N CCH3? CH3 CH3 lheat A) CH3CH2CH-CH2 B) CH3CH2C=CH2 CH3 C) CH3-C-CH3 CH2 D) CH3CHCH CH2 CH3 E) CH3CH-CH2 54) What is the product of the following reaction sequence? (CH3)2Culi Ho C CCH CCH CH2OH C CCHCH CH OH IIL. CH,OCH,CH,
Tulung ate n illud aludke place in a single step. In the Sn2 reaction, the nucleophile attacks the a-carbon from the backside and displaces the leaving group with an inversion of configuration occurring at the carbon. In the E2 elimination reaction, strong base removes an acidic hydrogen from the B-carbon and an alkene is formed as the leaving group is expelled from the a-carbon. This elimination follows Zaitsey's rule whereby the more substituted alkene is generally formed. In E2 elimination,...
please answer all parts, thanks!
1. More substituted alkenes are more stable than less substituted alkenes. Show the orbital overlap that helps to explain this observation. 2. Why is the heat of hydrogenation for an alkene exothermic? Analyze the bonds that are changing. AH = -30 kcal/mol Explain: + H2 3. Treating alkene "A" below with HBr can lead to a number of products. "A" SM + H-Br A bunch of products. For real, hella products. 3.A. Label the stereocenters...
1. [10 pts] Consider the elimination reaction for the following alkyl halide with sodium methoxide in methanol (Na* OCH, CH,OH). CH NaOme MeOH CH Compound A Problem 2c Draw the major expected organic product (a) Redraw Compound A as seen in Viewpoint I below left as a Newman projection on the template provided in Problem 2a (below). Hint: Fill in missing Hs ar C2 and C3 to help you get started! (b) Rotate the C2 C3 bond to obtain the...
How to properly solve these elimination and addition
reactions
Elimination and Addition reactions Purpose: Figuring out the ways that molecules react is the province of the mechanistic chemist. By understanding the mechanisms of reactions, the chemist can manipulate the experimental variables to favor one product over another. This element of control is the province of the synthetic organic chemist. This Workshop continues to explore how we know how molecules react and how this knowledge leads to control of the products....