Question

(39) What is the concentration of hydroxide ions in a solution given that the concentration of hydronium ions is 2.31 x 104 M
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Answer #1

For aqueous solutions, the following relationship  is always true:

Kw = [H3O+10H

And we know that the value of K_{w} = 10^{-14}

Putting the value of K_{w} \, \, and \, [H_{3}O^+] we get,

10^{-14}=[2.31*10^{-4}][OH^-]


therefore, we can find the он-

[OH^-]=\frac{10^{-14}}{2.31*10^{-4}}

[OH^-]=4.33*10^{-11} M

Therefore, The concentration of hydroxide ions comes out to be 4.33*10^{-11} M .
Option (B)

Important points:

  • Remember the formula Kw = [H3O+10H
  • pH+pOH=14 in the case when pH is given.
  • pH=-log[H_{3}O^+]
  • pOH=-log[OH^-]
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