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You are told that a basketball player spins the ball on his finger with an angular acceleration of 110 rad/s2. (10%) Problem

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Answer #1

Angular acceleration of the ball = \alpha = 110 rad/s2

Initial angular velocity of the ball = \omega1 = 0 rad/s (Starts from rest)

Final angular velocity of the ball = \omega2

Time period of acceleration = T = 2.5 sec

\omega2 = \omega1 + \alphaT

\omega2 = 0 + (110)(2.5)

\omega2 = 275 rad/s

Final angular speed of the ball = 275 rad/s

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