Question

) You need to set up a magnetic field perpendicular to the 5) An electron gun ends out a beam of electrons whose kinetic ener
0 0
Add a comment Improve this question Transcribed image text
Answer #1

5.

velocity of electron

0.5 m v^2 = U

0.5* 9.11* 10^-31* v^2 = 65* 10^-6* 1.6* 10^-19

v = 4778.29 m/s

now as we know

r = mv / qB

4* 10^-3 = 9.11* 10^-31* 4778.29 / ( 1.6* 10^-19* B)

B = 6.8* 10^-6 T

=======

plz post other problem separately

Comment before rate in case any doubt, will reply for sure.. goodluck

Add a comment
Know the answer?
Add Answer to:
) You need to set up a magnetic field perpendicular to the 5) An electron gun...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 5) An electron gun sends out a beam of electrons whose kinetic energies are all about...

    5) An electron gun sends out a beam of electrons whose kinetic energies are all about 53 μμeV. (1 μeV=1.6×10−25 J1 μeV=1.6×10−25 J.) You need to set up a magnetic field perpendicular to the beam that causes it to turn through a 90∘∘ circular arc of length 3 mm. How strong must the magnetic field be? [Note: electrons have a mass of about 9.11×10-31 kg.] 5) An electron gun sends out a beam of electrons whose kinetic energies are all...

  • 5) An electron gun sends out a beam of electrons whose kinetic energies are all about...

    5) An electron gun sends out a beam of electrons whose kinetic energies are all about 66 μμeV. (1 μeV=1.6×10−25 J1 μeV=1.6×10−25 J.) You need to set up a magnetic field perpendicular to the beam that causes it to turn through a 90∘∘ circular arc of length 5 mm. How strong must the magnetic field be? [Note: electrons have a mass of about 9.11×10-31 kg.]

  • Questions/Assignments an expression for the magnetic field at the center of circular loop of current carrying...

    Questions/Assignments an expression for the magnetic field at the center of circular loop of current carrying wire erive an expression for the magnetic field at a point on the axis of circular current carrying wire. 3. D erive an expression for the magnetic field at a point distance x away(along the dipole) due to magnetic dipole of moment M. 4. Derive an expression for the magnetic field at a point distance x away (along the perpendicular bisector) due to a...

  • A square loop of wire consisting of a single turn is perpendicular to a uniform magnetic...

    A square loop of wire consisting of a single turn is perpendicular to a uniform magnetic field. The square loop is then re-formed into a circular loop, which also consists of a single turn and is also perpendicular to the same magnetic field. The magnetic flux that passes through the square loop is 6.64 × 10-3 Wb. What is the flux that passes through the circular loop?

  • A square loop of wire consisting of a single turn is perpendicular to a uniform magnetic...

    A square loop of wire consisting of a single turn is perpendicular to a uniform magnetic field. The square loop is then re-formed into a circular loop, which also consists of a single turn and is also perpendicular to the same magnetic field. The magnetic flux that passes through the square loop is 7.91 × 10-3 Wb. What is the flux that passes through the circular loop?

  • 1. An electron moves in a circular path in the magnetic field of an electromagnet. The...

    1. An electron moves in a circular path in the magnetic field of an electromagnet. The plune of the electron's Sicular path is parallel to the smooth vole faces of the electromagnet. In the region where the electron is moving the magnetic field is uniform and has magnitude 0,50 T. The electron moves with a speed of 1.5 x 10 m/s. a. If someone could observe the electron from the north pole of the electromagnet, would the electron inove clockwise...

  • ***only the first question should be solved*** Paper 27 Magnetism 1. Find the magnetic field at...

    ***only the first question should be solved*** Paper 27 Magnetism 1. Find the magnetic field at the point O, if the current is I A and R-20 cm. 100 2. The two long straight wires each carry a current of 1-5 A in opposite directions and are separated by a distance d 30 cm. Find the magnetic field a distance 1- 20 cm to the right of t wire on the right. 3. A single-turn, circular loop of radius 10...

  • A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of...

    A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that an emf of 0.61 V and a current of 3.2 A are induced in the coil. The wire is the re-formed into a single-turn square coil, which is used in the same magnetic field (again perpendicular to the plane of the coil and with a magnitude changing at the same rate). What emf and current are induced in...

  • A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of...

    A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that an emf of 0.26 V and a current of 4.9 A are induced in the coil. The wire is then re-formed into a single-turn square coil, which is used in the same magnetic field (again perpendicular to the plane of the coil and with a magnitude changing at the same rate). What (a) emf and (b) current are...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT