Use the binomial distribution formula to determine the probability that in a carton of 18 eggs, that at least one 1 egg will be broken, if the probability of a broken egg is 0.08. Round your answer to the nearest hundredth.
P ( x = k ) = n ! k ! ( n − k ) ! p k ( 1 − p ) n − k
Hint: Use the complement rule. If at least one egg is broken, then that means 1 or 2 or 3 or....or all 18 eggs are broken. Whats missing from that list of possibilities?
Use the binomial distribution formula to determine the probability that in a carton of 18 eggs,...
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16. Let Y-number of broken eggs in a carton. The probability distribution for Y is given in the table below. Note: a carton of eggs contains 12 eggs. Probability | 0.7 1015 0.06 0.05 0.04 (a) Compute the expected value of Y and explain its meaning. Answer: E(Y) 0.58 (b) If 1,000 egg cartons are inspected, what would be the expected number of broken eggs found? Answer: 580 (c) Why is it that u is not...
3. (20 points) (a) Use the binomial probability formula to construct the probability distribution for Bernoulli trials with given number of trials n 5 and the probability of success p 0.35 x P(X x) (round to 4 decimals) 0 2 4 (b) What is the probability that X is 4? (c) What is the probability that X is at least 4? (d) Find the mean and the standard deviation ? of X (round to 2 decimals).
Compute PIX) using the binomial probability formula. Then determine whether the normal distribution can be used to estimate this probability. If so, approximate PX) using the normal distribution and compare the result with the exact probability n=47, p=0.5, and X = 21 For n = 47. p=0.5, and X = 21, use the binomial probability formula to find PC 0.0892 (Round to four decimal places as needed) Can the normal distribution be used to approximate this probability? O A. Yes,...
Assume that a procedure yields a binomial distribution with a trial repeated n = 18 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k = 0 successes given the probability p = 0.36 of success on a single trial.
Assume that a procedure yields a binomial distribution with a trial repeated n = 18 n=18 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k = 2 k=2 successes given the probability p = 0.29 p=0.29 of success on a single trial. (Report answer accurate to 4 decimal places.) P ( X = k ) = P(X=k)= * trying to do this in Exel so far all I have...
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all dont asnwer at all. I will thumbsdown. thanks
Let y denote the number of broken eggs in a randomly selected carton of one dozen eggs. Suppose that the probability distribution of v is as follows У01234 p(y) 0.64 0.20 0.11 0.04? (a) Only y values of 0, 1, 2, 3, and 4 have positive probabilities. What is p(4)? (Hint: Consider the properties of a discrete probability...
Compute P(x) using the binomial probability formula. Then determine whether the normal distribution can be used as an approximation for the binomial distribution. If so, approximate P(x) and compare the result to the exact probability. n = 50, p = 0.5, x = 25
Compute P(x) using the binomial probability formula. Then determine whether the normal distribution can be used as an approximation for the binomial distribution. If so, approximate P(x) and compare the result to the exact probability. n = 50, p = 0.5, x = 25
Assume that a procedure yields a binomial distribution with a trial repeated n = 8 times. Use either the binomial probability formula (or technology) to find the probability of k = 5 successes given the probability p = 0.31 of success on a single trial. (Report answer accurate to 4 decimal places.) P(X = k) = Submit Question Question 8 Assume that a procedure yields a binomial distribution with a trial repeated n = 15 times. Use either the binomial...
Assume that a procedure yielids a binomial distribution with a trial repeated n times Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial n-18,x 14,p 0.75 (1)(Round to three decimal places as needed )