here,
r1 = 0.22 cm = 0.0022 m
r2 = 0.85 cm = 0.0085 m
volume flow rate , V = 0.45 L/s
V = 4.5 * 10^-4 m^3 /s
a)
let the speed of water be v2
V = pi * r2^2 * v2
4.5 * 10^-4 = pi * 0.0085^2 * v2
v2 = 1.98 m/s
the maximum height , h2 = v2^2 /( 2g)
h2 = 1.98^2 /(2 * 9.81) m
h2 = 0.2 m
b)
let the speed of water be v1
V = pi * r1^2 * v1
4.5 * 10^-4 = pi * 0.0022^2 * v1
v1 = 29.6 m/s
the maximum height , h1 = v1^2 /( 2g)
h1 = 29.6^2 /(2 * 9.81) m
h1 = 44.7 m
Please answer all parts of the question. Pad. Compare D strength and cr |□ 139063244.pdf π...
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