Question

Class Management I Help Magnetic fields and forces Begin Date: 2/21/2017 12:00:00 AM Due Date: 2/27/2017 5:00:00 PM End Date: 3/9/2017 5:00:00 PM (9%) Problem 5: A 200 turn circular loop of radius 65 cm is vertical, with its axis on a line running east to west. A current of 95 A circulates clockwise in the loop when viewed from the east. The Earth's field here is due north, parallel to the ground, with a strength of 3.1 x 10 5 T. A What is the magnitude of the torque on the loop, in N.m? Grade Summar Deductions Potential sino cos0 tan 7 8 9 Submissions HOME Attempts remain 4 5 6 cotan0 asino acos0 (406 per attempt detailed view 2 3 atan0 acotano sinh0 cosh0 tanh0 cotanh0 vo Degrees Radians BACKSPACE Hint Feedback Submit give up Hints: 4% deduction per hint. Hints remaining: 3 Feedback: 5% deduction per feedback. Submission History Answer Hints Feedback To Totals All content C 2017 Expert TA, LLC
I need help with these two problems! #8 has three parts i cant figure out!

Answer 1

Solution Problem 5 Torque on the loop τ=NIAB sin θ 200turns x95A x3.14x 65x10-2mx3.1x10-5Txsin90 -0.7813Nm Therefore, magnitude of torque on the loop is 0.7813Nm Problem 8 Alpha particle is basically a helium atom a- He Atomic mass of nucleus is 4amu Alpha particles contains 2 protons and 2 neutron. hence, charge of an atom is q 9Fe = 2e Therefore, charge of an alpha particle is 2e

Radius of curvature mV Bg 4x1.67x10 kg x1.1x10'm/s 1.6x 2x1.6x10-19 -1.43x10-m Therefore, radius of curvature of alpha particle is 1.43x10 m