All in MATLAB
mixing_ratio function:
function w = mixing_ratio(P,T) %function mixing_ratio has 2 inputs P in millibars and T in K
Po = 1013.246;
To = 373.16;
a1 = 11.344*(1-T/To);
a2 = -3.49149*(To/T - 1);
b1 = -7.90298*(To/T - 1);
b2 = 5.02808*log10(To/T);
b3 = -1.3816*(10^a1 -1)/(10^7);
b4 = 8.1328*(10^a2 -1)/(10^3);
b5 = log10(Po);
b = b1 + b2 + b3 + b4 + b5;
Pv = 10^b;
w = 0.62197*Pv/(P - Pv);
end
%mixing_ratio.m
function w = mixing_ratio(P,T) %function mixing_ratio has 2
inputs P in millibars and T in K
Po = 1013.246;
To = 373.16;
a1 = 11.344*(1-T/To);
a2 = -3.49149*(To/T - 1);
b1 = -7.90298*(To/T - 1);
b2 = 5.02808*log10(To/T);
b3 = -1.3816*(10^a1 -1)/(10^7);
b4 = 8.1328*(10^a2 -1)/(10^3);
b5 = log10(Po);
b = b1 + b2 + b3 + b4 + b5;
Pv = 10^b;
w = 0.62197*Pv/(P - Pv);
end
%wetBulb.m
%Prompt the user for Temperature
Ta = input('Enter air temperature in degK: ');
Td = input('Enter dew temperature in degK: ');
%Prompt user for atmospheric pressure
pa = input('Enter atmospheric pressure in hPa: ');
%Call for function mixing_ratio to calculate w1 and w2
w1 = mixing_ratio(pa, Td);
w2 = mixing_ratio(pa, Ta);
%Calculate the wetbulb temperature
cp = 1005;
L = 2.501*10^6;
delQ = (L/(1+w2))-(cp*(Ta - Td))*(1+0.8*w2);
%Print the results
fprintf("w1 = %f\nw2 = %f\nWetbulb temperature = %f\n", w1, w2,
delQ);
Screenshot of Code Screen:
Screenshot of Output:
All in MATLAB mixing_ratio function: function w = mixing_ratio(P,T) %function mixing_ratio has 2 inputs P in...
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