Question

A plane is dropping survey markers in a remote location. The plane is flying with a constant velocity of 76 m/s. The pilot has his sights set so that the marker target zone appears in the sights 715m before the plane passes over that zone. The pilot will drop a marker at the same time the zone appears in the sights. The marker is released with zero velocity relative to the plane. At what altitude, h, does the pilot need to be flying for his markers to land in the target zone? [The units for your answer will be meters, expressed to the nearest integer value.]

Answer 1

S = distance of marker = 715 m H = height of plane from which marker is to be neglected V_x = horizontal velocity (does not changes: which is initially given by the plane)here V_x = 76m /s (since it is released with zero velocity to plane) v_ y I = initial vertical velocity = (here it is zero) V_y f = final vertical from the basic equation t = s/v_x we can final the time of flint t = 715/76 = 9.4075 In vertically direction there is only acceleration is acting down wands hence a = -g T - find height of plane we can use the equation - H= V_y I x t + 1/2 a t^2 hence sign concentration is important H(- H)since it is following - H = 0 times t - 1/2 9.8 times (9 407)^2 H = 434.05 m so, the plane should fly at a height of 454 04m to success fully set the marker