A survey of several 11 to 12 year olds recorded the following amounts spent on a...
A survey of several 11 to 12 year olds recorded the following amounts spent on a trip to the mall: $21.42,$20.66,$19.01,$27.39,$25.23,$23.70,$28.62 Construct the 99% confidence interval for the average amount spent by 11 to 12 year olds on a trip to the mall. Assume the population is approximately normal. Step 2 of 4 : Calculate the sample standard deviation for the given sample data. Round your answer to two decimal places.
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A survey of several 11 to 12 year olds recorded the following
amounts spent on a...
A survey of several 11 to 12 year olds recorded the following amounts spent on a...
A survey of several 11 to 12 year olds recorded the following amounts spent on a trip to the mall: $18.35, $25.19, $27.45 Construct the 80 % confidence interval for the average amount spent by 1 l to 12 year olds on a trip to the mall. Assume the population is approximately normal. Copy Daa Step 3 of 4: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places Tables...
A survey of several 9 to 11 year olds recorded the following amounts spent on a...
A survey of several 9 to 11 year olds recorded the following amounts spent on a trip to the mall: $22.91,$17.13,$13.60 Construct the 99% confidence interval for the average amount spent by 9 to 11 year olds on a trip to the mall. Assume the population is approximately normal. Step 1 of 4: Calculate the sample mean for the given sample data. Round your answer to two decimal places. Step 2 of 4: Calculate the sample standard deviation for the...
A survey of several 88 to 1010 year olds recorded the following amounts spent on a...
A survey of several 88 to 1010 year olds recorded the following amounts spent on a trip to the mall: $19.02,$21.15,$22.96,$27.58$19.02,$21.15,$22.96,$27.58 Construct the 99%99% confidence interval for the average amount spent by 88 to 1010 year olds on a trip to the mall. Assume the population is approximately normal. Copy Data Step 4 of 4: Construct the 99%99% confidence interval. Round your answer to two decimal places.
A survey of several 9 to 11 year olds recorded the following amounts spent on a trip to the mall: $24.73,$24.85,$22.86,$...
A survey of several 9 to 11 year olds recorded the following amounts spent on a trip to the mall: $24.73,$24.85,$22.86,$23.81,$21.31,$17.40 Construct the 80% confidence interval for the average amount spent by 9 to 11 year olds on a trip to the mall. Assume the population is approximately normal. Step 1 of 4: Calculate the sample mean for the given sample data. Round your answer to two decimal places. Step 2 of 4: Calculate the sample standard deviation for the...
step 2: calculate the sample standard deviation from the given sample. round to two decimal places...
step 2: calculate the sample standard deviation from the given
sample. round to two decimal places
step 3: find the critical value that is used in confidence
interval
step 4: construct 80% confidence interval. round to two
decimal place
step 2: find the critical value. round to 3 decimal
place
step 3: find the standard deviation of the paired
differences
step 4:construct 99% confidence interval. round to one decimal
place
A survey of several 9 to 11 year olds recorded...
17) In a survey, 26 people were asked how much they spent on their child's last...
17) In a survey, 26 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $32 and standard deviation of $14. Construct a confidence interval at a 90% confidence level. Give your answers to one decimal place. Enter the confidence interval in the form: Sample Mean ± Margin of Error You intend to estimate a population mean μμ with the following sample. 13 17 13 14 11 16...
The following data show the number of hours per day 12 adults spent in front of...
The following data show the number of hours per day 12 adults spent in front of screens watchin 4.3 4.5 7.4 1.3 5.7 4.6 3.4 7.9 2.2 5.1 1.7 8.3 a. Construct a 99% confidence interval to estimate the average number of hours per day adults s The 99% confidence interval to estimate the average number of hours per day adults spend (Round to two decimal places as needed.) b. What assumptions need to be made about this population? O...
The following data show the number of hours per day 12 adults spent in front of...
The following data show the number of hours per day 12 adults spent in front of screens watching television-related content. Complete parts a and below. 1.3 5.7 4.6 3.4 4.3 5.1 7.9 7.40 8.3 1.7 2.2 a. Construct a 99% confidence interval to estimate the average number of hours per day adults spend in front of screens watching television-related content. The 90% confidence interval to estimate the average number of hours per day adults spend in front of screens watching...
4. A survey asked a random sample of 363 first-year students how many hours they studied...
4. A survey asked a random sample of 363 first-year students how many hours they studied during a particular week. The mean was 15.3 hours. Suppose we know that the population standard deviation is 8.5 hours. Construct a 90%, 95% and 99% confidence interval for the mean study time of all first year students at this university. Interpret the 90% confidence interval.
The following measurements (in picocuries per liter) were recorded by a set of carbon monoxide detectors...
The following measurements (in picocuries per liter) were recorded by a set of carbon monoxide detectors installed in a waste disposal facility: 487.4,473.8,534.3 Using these measurements, construct a 95% confidence interval for the mean level of carbon monoxide present in the facility. Assume the population is approximately normal. step 1: sample mean round two decimal places step 2 sample standard deviation two decimal places step 3 find critical vaue of confidence level round three decimal places step 4 contruct the...
A survey of several 11 to 12 year olds recorded the following amounts spent on a trip to the mall: $18.35, $25.19, $27.45 Construct the 80 % confidence interval for the average amount spent by 1 l to 12 year olds on a trip to the mall. Assume the population is approximately normal. Copy Daa Step 3 of 4: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places Tables...
step 2: calculate the sample standard deviation from the given
sample. round to two decimal places
step 3: find the critical value that is used in confidence
interval
step 4: construct 80% confidence interval. round to two
decimal place
step 2: find the critical value. round to 3 decimal
place
step 3: find the standard deviation of the paired
differences
step 4:construct 99% confidence interval. round to one decimal
place
A survey of several 9 to 11 year olds recorded...
The following data show the number of hours per day 12 adults spent in front of screens watchin 4.3 4.5 7.4 1.3 5.7 4.6 3.4 7.9 2.2 5.1 1.7 8.3 a. Construct a 99% confidence interval to estimate the average number of hours per day adults s The 99% confidence interval to estimate the average number of hours per day adults spend (Round to two decimal places as needed.) b. What assumptions need to be made about this population? O...
The following data show the number of hours per day 12 adults spent in front of screens watching television-related content. Complete parts a and below. 1.3 5.7 4.6 3.4 4.3 5.1 7.9 7.40 8.3 1.7 2.2 a. Construct a 99% confidence interval to estimate the average number of hours per day adults spend in front of screens watching television-related content. The 90% confidence interval to estimate the average number of hours per day adults spend in front of screens watching...
4. A survey asked a random sample of 363 first-year students how many hours they studied during a particular week. The mean was 15.3 hours. Suppose we know that the population standard deviation is 8.5 hours. Construct a 90%, 95% and 99% confidence interval for the mean study time of all first year students at this university. Interpret the 90% confidence interval.
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