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Consider the closed Gaussian surface shown in the diagram. It is a cuboid of height 2.55...
A closed surface with dimensions a = b = 0.400 m and c = 0.800 m...
A closed surface with dimensions a = b = 0.400 m and c = 0.800 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and given by E = [(5.00xy)i + (5.00x2y)j ] N/C, where y is in meters. 3) Calculate the net electric flux leaving the closed surface. 4) What net charge is enclosed by the...
PHYSICS charge questions A closed surface with dimensions a = b = 0.400 m and c...
PHYSICS charge questions
A closed surface with dimensions a = b = 0.400 m and c = 0.800 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region Is nonuniform and given by E = (3.40 + 3.20 x2)? N/C, where x is in meters. (a) Calculate the net electric flux leaving the closed surface. N.m^2/C (b) What net charge is...
Please show all work thank you! A closed surface with dimensions a b- 0.400 m and...
Please show all work thank you!
A closed surface with dimensions a b- 0.400 m and c 0.700 m s located as shown in the figure below. The left edge of the closed surface is located at position x a. The electric field throughout the region is nonuniform and given by E- (4.40 3.8ox2) i N/c, where x is in meters. x F a (a) Calculate the net electric flux leaving the closed surface N me/C (b) What net charge...
The diagram shows a closed triangular prism situated in a region of uniform electric field E...
The diagram shows a closed triangular prism situated in a region of uniform electric field E = (6.84 x 10^4 j) N/C. The dimensions of the triangular prism are a = 18.0 cm, b = 10.0 cm, and d = 32.4 cm. Note that the diagram is not to scale. (a) What is the flux through the bottom face of the triangular prism? What is the direction of the normal for the bottom face of the triangular prism? How is...
please answer both 8.04 x 104 N/C as shown in the fiqure below Consider a closed...
please answer both
8.04 x 104 N/C as shown in the fiqure below Consider a closed triangqular box resting within a horizontal electric field of maqnitude E 30.0 cm 60.0 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box m2/c What is the direction of the normal vector for this surface? kN (b) Calculate the electric flux through the slanted surface of the box kN m2/c An uncharged nonconductive hollow sphere of radius 16.0...
Problem A.1 - Calculate electric flux f5) The electric field due to an infinite line of...
Problem A.1 - Calculate electric flux f5) The electric field due to an infinite line of charge is perpendicular to the line and has magnitude E . Consider an imaginary cylinder with radius e-25 cm and length L = 40 cm that has an infinite line of positive charge running along its axis. The charge per unit length is 3 HC/m. Do not use Gauss's Law, but actually calculate the flux! a) What is the electric flux through the cylinder...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...
A closed surface with dimensions a = b = 0.400 m and c = 0.800 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and given by E = [(5.00xy)i + (5.00x2y)j ] N/C, where y is in meters. 3) Calculate the net electric flux leaving the closed surface. 4) What net charge is enclosed by the...
PHYSICS charge questions
A closed surface with dimensions a = b = 0.400 m and c = 0.800 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region Is nonuniform and given by E = (3.40 + 3.20 x2)? N/C, where x is in meters. (a) Calculate the net electric flux leaving the closed surface. N.m^2/C (b) What net charge is...
Please show all work thank you!
A closed surface with dimensions a b- 0.400 m and c 0.700 m s located as shown in the figure below. The left edge of the closed surface is located at position x a. The electric field throughout the region is nonuniform and given by E- (4.40 3.8ox2) i N/c, where x is in meters. x F a (a) Calculate the net electric flux leaving the closed surface N me/C (b) What net charge...
The diagram shows a closed triangular prism situated in a region of uniform electric field E = (6.84 x 10^4 j) N/C. The dimensions of the triangular prism are a = 18.0 cm, b = 10.0 cm, and d = 32.4 cm. Note that the diagram is not to scale. (a) What is the flux through the bottom face of the triangular prism? What is the direction of the normal for the bottom face of the triangular prism? How is...
please answer both
8.04 x 104 N/C as shown in the fiqure below Consider a closed triangqular box resting within a horizontal electric field of maqnitude E 30.0 cm 60.0 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box m2/c What is the direction of the normal vector for this surface? kN (b) Calculate the electric flux through the slanted surface of the box kN m2/c An uncharged nonconductive hollow sphere of radius 16.0...
Problem A.1 - Calculate electric flux f5) The electric field due to an infinite line of charge is perpendicular to the line and has magnitude E . Consider an imaginary cylinder with radius e-25 cm and length L = 40 cm that has an infinite line of positive charge running along its axis. The charge per unit length is 3 HC/m. Do not use Gauss's Law, but actually calculate the flux! a) What is the electric flux through the cylinder...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...
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