Question

please dont use thus formula 1/2mV = mgy

<Test IlII Problems Problem 2 ed 2 of 3 Complete Constants Part A A spring with k-58 N/m hangs vertically next to a ruler. The end of the spring is next to the 19-Cm If a 3.0-kg mass is now attached to the end of the spring, and the mass is allowed to fall, where will the end of the spring line up with the ruler marks when the mass is at its lowost position? mark on the ruler ode... Express your answer to two significant figures and include the appropriate units. hr I- 120 cm ube Subm Previous Answers com... Correct rship APPL u Provide Feedback Next X Goo.. UTube il.com ers and Cam... based.. ent ensure more vi.. MacBook Pro

Answer 1

Use law of conservation of energy

Spring potential energy = gravitational energy of the mass

1/2kx^2=mgh

H= elongation of the spring = x

1/2kx^2 = mgx

kx^2= 2mgx

kx=2mg

x=2mg/k

x=(2*3*9.8)/58

x=1.01 m = 101cm

End of the spring = original length+spring elongation = 19cm+101cm = 120 cm