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5.Use polar coordinates system to evaluate: x2 + y2)dydx , R is the region enclosed by...
3. Draw the region D and evaluate the double integral using polar coordinates. dA, D= {(x, y)| x2 + y² <1, x +y > 1} (b) sin(x2 + y2)dA, D is in the third quadrant enclosed by D r? + y2 = 7, x² + y2 = 24, y = 1, y = V3r.
3. Draw the region D and evaluate the double integral using polar coordinates. (a) SI x + y dA, x2 + y2 D= {(x, y)| x2 + y2 < 1, x + y > 1} D (b) ſ sin(x2 + y2)dA, D is in the third quadrant enclosed by m2 + y2 = 71, x2 + y2 = 27, y=x, y= V3x.
(1 point) Using polar coordinates, evaluate the integral ST sin(x2 + x>)dA where Ris the region 1 5x2 + y2 549. 1.080
3. Let D be the region in the first quadrant lying inside the disk x2 +y2 < 4 and under the line y-v 3 x. Consider the double integral I-( y) dA. a. Write I as an iterated integral in the order drdy. b. Write I as an iterated integral in the order dydx c. Write I as an iterated integral in polar coordinates. d. Evaluate I
Q4: Use polar coordinates to evaluate x2 - y2 dA, where R is the region in the first V9- quadrant within the circle x2 + y2-9.
11. Use polar coordinates to evaluate the integral 1,8-2V(+ y2)<dy dx
Use cylindrical coordinates to calculate : x2 + y2 dVW : x² + y2 < 64, 05234 SS/(x2 + y2)dV =
2. Let R be the region R = {(X,Y)|X2 + y2 < 2} and let (X,Y) be a pair of random variables that is distributed uniformly on this region. That is fx,y(x, y) is constant in this region and 0 elsewhere. State the sample space and find the probability that the random variable x2 + y2 is less than 1, P[X2 +Y? < 1].
2. Find the area of the plane figure defined by the inequalities : x2 + y2 <9; x2 + y2 - 6x S 0; (in the first quadrant). Use polar coordinates.
Use polar coordinates to evaluate the integral where R is the region in in the first quadrant enclosed by the circumference x2+y2=4 and the lines x=0 and y=x SUR (60 - 3y)dA Use coordenadas polares para evaluar la integral JR (6x – 3y)dA donde R es la región en en el primer cuadrante encerrada por la circunferencia za + y2 = 4y las rectas r = Oyy=2. 0-8+12V2 O NO ESTÁ LA RESPUESTA O 16 - 12/2 O 12 -...