Question

Furnace 02 H20 absorber CO, absorber Sample A 8.222 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 20.74 grams of CO2 and 3.640 grams of H20 are produced. In a separate experiment, the molar mass is found to be 122.1 g/mol. Determine the empirical formula and the molecular formula of the organic compound. Enter the elements in the order C, H, O empirical formula molecular formula

Answer 1

wt с of 10 Cx Hyo co + H₂O No. of moles oq ez = 20.744 602X Imol.coz 44.0 g co2 -0.47136 mol 0.47136 mol c X 12.0114c molc = 5:662 g of c No. of mol of n = 3,640 g H20 x 1 mol H2o. 1800 g H₂0 0,2034 mol H2O weight of =280.2034 그 0.40688x1= 0.40688 8.222 - (5. 5.662+0.40688) 2.15312 gm No of moks fo 215312 x lmolo 16 13457 C=0.47136 smallest moler mass H= 0,4644 o-013457 (23.5) H=3 Empirical formularbruss = 40+3+ 16 = 59 Ratio : 122.1 u 2 59 Emprical formular (3 g H30 Moleculen formula = qH02 g 15 mass of o O 20 2

co + H₂O CxHy Ho of moles ofc 24 g co2 S0215514_mol 6.826g co2 Almolo2 No 는 of moles Loy imol H₂O 2,795 g H₂O of ho 18:0g the 0.155-28 mol. of moles of h 0.15528x2=31056 mol Emprical formula a [C Hq Emprical formula mass= 3 12+2 -14 g/mol. Molan mas 20.05. Ratio Moleculen Mass - 20.05? Emp. Mass 14.0 Molecular formula i Ca Hy Emprical formula CHZ - 2 = C