Question

Help Save & Exit Submit Required information A Brayton cycle with regeneration using air as the working fluid has minimum and maximum temperatures in the cycle are 310 and 1150 K. Assume an isentropic efficiency of 75 percent for the compressor and 82 percent for the turbine and an effectiveness of 68 percent for the regenerator. Use variable specific heats for air a pressure ratio of 7. The Determine the air temperature at the turbine exit. (You must provide an answer before moving on to the next part) The air temperature at the turbine exit is

Answer 1

Given data

minimum temperature - temperature at compressor inlet

T-310 K

P2 Ps Pressure ratio (rp) =-=-= 7

maximum temperature means turbine at inlet

T3-1150 K

Isentropic efficiency of turbine (nr ) = 0.82

Isentropic expansion process occur in turbine

$\frac{T_{3}}{T'_{4}}=\left ( \frac{P_{3}}{P_{4}} \right )^{\frac{\gamma -1}{\gamma }}$

1150 = (7) т, 1.4-1 TT

$T'_{4}=659.54\textup{ K}$

$\textup{Isentropic efficiency of turbine}$

$\eta _{T}=\frac{T_{3}-T_{4}}{T_{3}-T'_{4}}$

1150 T4 0.82 = 1150-659.54

$T_{4}=747.823\textup{ K}$

$\textup{Air temperature at turbine exit is 747.823 K}$