Question

Estimate the wavelength of maximum absorption for the octahedral ion hexaamminecobalt(lII) from right the fact that light transmitted by a solution of it is yellow-orange. Hint: use the color wheel to the 620 nm 800 nm 400 nm 580 nm nm Estimate the crystal field splitting energy Ap (in kJ mol) kJ mol-l 430 nm 490 nm Retry Entire Group 9 more group attempts remaining
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Answer #1

Ans. Step 1: Determine wavelength of absorbed light:

The color of light being absorbed is OPPSOITE to the color being transmitted (perceived by our eyes) in the color wheel.

So,

            Color of absorbed light = blue-violet (opposite to yellow-orange)

            And, wavelength of absorbed light = 430 nm (opposite to 580 nm)

# Step 2: Determine crystal field splitting energy (CFSE)


# Crystal field splitting energy (CFSE/10 is given by Ag = h v = Eight -Equation 1 - Equation 2 Where, h Planks constant 6.626E-34 Js Elight Energy of photon c 99792458 ms 2wavelength430 nm4.30E-07 m Speed of light = 2 # Putting the values in equation 2- 6.626E-34 Js x 299792458 m s Ao 4.62E-19 J 4.30E-07 m So, ?? for one single complex 4.62E-19 J complex-1 # Now, for CFSE for 1 mole complex 4.62E-19 J complex-1 - 2.78E+05 J mol1 = 2.78E-02 J mol-1-278.19 kJ mol-1 Ag = 6.02E-23 complex mol-1 x

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