Question

THIS IS NOT A EXAM NOR GRADED ASSIGNMENT SIMPLY A REVIEW PREPARING ME FOR THE TEST GIVING GOOD FEEDBACK

Consider this circuit: (A is 10 V; B is 6 V; Xis 2 ohms; Y is 4 ohms and Z is 8 ohms. A -В OY Determine the current flow through resistor Y. 1.21 A 2.32A 1.64 A 4.22 A

Answer 1

z I لها Iz • Iz A B 0 2 Given A = lov x = على ت I B=6v y = 42, Z= 82 Let from A current - I from B current = I. Hence It I ₂ = I3 Using KVL for loop 6 21, +4I3 = 10 I +213 = 5 For loop 6 8 Iz + 4 I3 = 6 4 Iz + 2 Iz = 3 Putting Iz= II t Iz For loop I, + 2(1,+I)- 5

3 Il + 2 I2 = 5 2 for loop 417 + 2(1,+I,)- 3 6 I2 + 21, = 3 Solving for loop 6 a 3 I + 2 Iz Ix2 21, +61= 3]*3 61 +41% = 10 6/1, + 18 I2 = 9 = 5 -14 Iz Iz = - 14 5 + 2x 2X - A I= 12 A In + I= 444) Hence. cwerent through Y Iz = It Iz = 23 = 1:64A 14 1:64A Option (c) is connect
Answer