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The air in a room with volume 180 m contains o.19 carbon dioxide initially, fresher air with only 0.05% carbon dioxide flows



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dt dt het PCt) be the percentage of carbon dioxide at timet Here tis in minutes Volume of room= 180m Amount of Carbon DioxideSince So Dividing y is continou, y/o) 0.18, and the right hand side is never zero, we deduce 9-100y is always negative 19.100

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