Three resistors in a series connected to a battery A 2.90 Ω resistor, a 5.79 Ω...
Three resistors in a series connected to a battery
A 2.90 Ω resistor, a 5.79 Ω resistor, and a 9.96 Ω resistor are connected in series with a 15.0 V battery. What is the equivalent resistance?
What is the current in each resistor?
Homework Answers
The three resistors are connected in series.
So, the equivalent resistance -
Req = R1 + R2 + R3 = 2.90 + 5.79 + 9.96 = 18.65 ohm.
In series combination, current through each resistor is the same.
And magnitude of current through each resistor = 15 / 18.65 = 0.80 A.
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