Question

Q2. Block A, which has a weight of 10 N, stays at rest at the initial position. The spring, which has a stiffness of K-200 N/m, is compressed by 10 cm and then released. If the coefficient of kinetic friction between the block and the surface is px -0.2, determine the acceleration of the block just after the spring is released. wa

Answer 1

Ans) Given,

Weight of block (mg) = 10 N

Stiffness of spring (K) = 200 N/m

Compression of spring (x) = 10 cm or 0.1 m

Equating forces along horizontal direction,

=> Kx - $\mu_k$ mg = m a

where, a = acceleration of block

m = Mass of block = 10 N / 9.81 = 1.019 kg

=> (200 x 0.1) - (0.20 x 10) = 1.019 a

=> 1.019 a = 20 - 2

=> 1.019 a = 18

=> a = 17.66 m/$s^2$

Hence, acceleration of block is 17.66 m/$s^2$