10. Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according...
10. Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according to
BaO2(s)+H2SO4(aq)->BaSO4(s)+H2O2(aq)
How many milliliters of 4.25 M H2SO4(aq) are needed to react completely with 58.9 g of BaO2(s)?
Homework Answers
Moles of BaO2 = 58.9 / 169.33 = 0.348 moles
=> Moles of H2SO4 required = 0.348
=> 0.348 = 4.25 x V
=> V = 0.08185 liters = 81.85 mL
Add Answer to:
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