An open water jet exits from a nozzle into sea-level and strikes a stagnation tube If...

Question

Question

Answer 1

Answer #1

P1 = 110kPa

P3 = P2 = Patm = 101.35kPa

a)

Let V1 and V3 be velocity of water at point 1 and 3 respectively.

A3/A1 = area ratio at point 1 and 3 = (4/12)^2 = 1/9

V1 = V3*A3/A1 = V3/9 ____________________ eq.1

using Bernoulli theorem between point 1 and 3,

(P1 - P3)/1000 = (V3^2 - V1^2)/2

or

(110 - 101.35)*1000/1000= 40*V3^2/81

=> V3 = 4.185m/s

and V1 = 0.465m/s

b)

H = P3/1000/9.81 = 101.35*1000/1000/9.81 = 10.33m

Answer 2

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