Given:
Virtual Address size of the machine: 16bits
Page Size : 8Kb
Thus, before calculating each address is to converted into the number of bytes
Therefore
Virtual address size = 2^16 bytes
Page Size = 2^13 bytes
Now using the formula
Number of entries in page table = (virtual address space size)/(page size)
Number of pages = (2^16)/(2^13) = 2^3
Thus,
Number of pages of virtual address space = 2^3
A machine has a 16-bit byte-addressable virtual address space. The page size is 8 KB. How...
3. Virtual Memory (20 points) An ISA supports an 8 bit, byte-addressable virtual address space. The corresponding physical memory has only 256 bytes. Each page contains 32 bytes. A simple, one-level translation scheme is used and the page table resides in physical memory. The initial contents of the frames of physical memory are shown below. VALUE address size 8 bit byte addressable each byte of addressing type memory has its own address 32 B page size physical memory size 256...
Consider a virtual memory system with the following properties: 36 bit virtual byte address, 8 KB pages size, and 32 bit physical byte address. Please explain how you determined your answer. a. What is the size of main memory for this system if all addressable frames are used? b. What is the total size of the page table for each process on this processor, assuming that the valid, protection, dirty, and use bits take a total of 4 bits and...
A certain byte-addressable computer system has 32-bit words, a virtual address space of 4GB, and a physical address space of 1GB. The page size for this system is 4 KB. Assume each entry in the page table is rounded up to 4 bytes. a) Compute the size of the page table in bytes. b) Assume this virtual memory system is implemented with a 4-way set associative TLB (Translation Lookaside Buffer) with a total of 256 address translations. Compute the size...
A computer system has a 36-bit virtual address space with a page size of 8K, and 4 bytes per page table entry. How many pages are in the virtual address space? What is the maximum size of addressable physical memory in this system? If the average process size is 8GB, would you use a one-level, two-level, or three-level page table? Why? Compute the average size of a page table in part c above
A computer uses a byte-addressable virtual memory system with a four-entry TLB and a page table for a process P. Pages are 16 bytes in size. Main memory contains 8 frames and the page table contains 16 entries. a. How many bits are required for a virtual address? b. How many bits are required for a physical address?
Question 2 Suppose you have a byte-addressable virtual address memory with 8 virtual pages of 64 bytes each and 4 page frames. Assuming the following page table, Page = Frame Valid Bit 0 0 1 2 3 4 5 What physical address corresponds to the virtual address 0X44 a. OXC1 b.OXC2 COXC4 d. OXCO OXC3
Suppose you have a byte-addressable virtual address memory system with 8 virtual pages of 64 bytes each, and 4-page frames. Assuming the following page table, answer the questions below: Page #Frame #Valid Bit0111312-03014215-06-07-0a) How many bits are in a virtual address? b) How many bits are in a physical address? c) What physical address corresponds to the following virtual addresses (if the address causes a page fault, simply indicate this is the case)? 1) Ox00 2) 0x44 3) OxC2 4) 0x80
Virtual memory address translation: a) Consider a machine with a physical memory of 8 GB, a page size of 4 KB, and a page table entry size of 4 bytes. How many levels of page tables would be required to map a 52-bit virtual address space if every page table fits into a single page? b) Without a cache or TLB, how many memory operations are required to read or write a page in physical memory? c) How much physical...
Problem #1 (25 points) Address Space, Memory Consider a hypothetical 18-bit processor called HYP18 with all registers, including PC and SP, being 18 bits long. The smallest addressable unit in memory is an 8-bit byte. A. (4 points) What is the size of HYP18's address space in bytes and KB? How many address lines does HYP18 require? Address space: Bytes Address space: KB (KiloBytes). Address bus lines: B. (6 points) Assume that first quarter of the address space is dedicated...
For a 2-way set associative cache with an 8-bit byte addressable address and 8- byte blocks, what is the maximum number of sets in the cache?