For a 2-way set associative cache with an 8-bit byte addressable address and 8- byte blocks, what is the maximum number of sets in the cache?
For a 2-way set associative cache with an 8-bit byte addressable address and 8- byte blocks,...
Consider a 2-way set associative cache consisting of 8 blocks total of byte-addressable memory with 4 bytes per block. Assume that the cache is initially empty. Given the following address sequence, fill in the table below. Time Access Tag Set Offset 3 10010001 11001001 10110110 10101011 10110010
Suppose we have a byte-addressable computer with a cache that holds 8 blocks of 4 bytes each. Assuming that each memory address has 8 bits and cache is originally empty, for the cache mapping technique, two-way set associative, trace how cache is used when a program accesses the following series of addresses in order: 0x01, 0x04, 0x09, 0x05, 0x14, 0x21, and 0x01.
) Consider an 8-way associative 64 Kilo Byte cache with 32 byte cache lines. Assume memory addresses are 32 bits long. a). Show how a 32-bit address is used to access the cache (show how many bits for Tag, Index and Byte offset). b). Calculate the total number of bits needed for this cache including tag bits, valid bits and data c). Translate the following addresses (in hex) to cache set number, byte number and tag (i) B2FE3053hex (ii) FFFFA04Ehex...
A direct-mapped cache consists of 8 blocks. Byte-addressable main memory contains 4K blocks of 8 bytes each. Access time for the cache is 22ns, and the time required to fill a cache slot from main memory is 300ns. (This time allows us to determine the block is missing and bring it into cache.) Assume a request is always started in parallel to both cache and to main memory(so if it is not found in cache, we do not have to...
Q2. Consider a four-way set associative cache with a data size of 64 KB. The CPU generates a 32-bit byte addressable memory address. Each memory word contains 4 bytes. The block size is 16 bytes. Show the logical partitioning of the memory address into byte offset, cache index, and tag components.
Memory Hierarchy and Cache Consider a computer with byte-addressable memory. Addresses are 24-bits. The cache is capable of storing a total of 64KB of data, and frames of 32 bytes, Show the format of a 24-bit memory address for: a- Direct mapped cache b- 2-way associative cache c- 4-way associative cache d- For each type of cache above, indicate where would the reference memory address 0DEFB6 map
Consider a processor that has a 20-bit address and a 1K Byte Cache. The cache and main memory are divided into blocks where each block is 256 Bytes. If direct mapping is used, what is the tag size of each block in cache and how many tag comparisons are made for a one-cache access? Repeat part (1) for fully associative mapping. Repeat part (1) for 2 way set-associative cache. For the direct map find out which of the following accesses...
Suppose a computer using a fully associative cache has 232 bytes of byte-addressable main memory and a cache of 1024 blocks, were each cache block contains 32 bytes. Consider a memory address as seen by the cache. How many bits are in the tag field?
Cache of 4096 blocks, a 4-word block size, and a 32-bit address, find the total number of sets and the total number of tag bits for caches that are direct mapped, four-way set associative, and fully associative.
Set-Associative Cache. Memory is byte addressable. Fill in the missing fields based upon the properties of a set-associative cache. Click on "Select" to access the list of possible answers. Set Block Size Number of Tag Bits Select] Select] Main Memory Size Cache Size 256 B 1) 128 KiB 16 KiB 2) 32 GiB 32 KiB 1 KiB 3) [Select ] 512 KiB 1 KiB [Select ] 10 16 GiB 4 KiB Select ] I Select ] 5) 10 64 MiB...