Consider a processor that has a 20-bit address and a 1K Byte Cache. The cache and...
Consider a processor that has a 20-bit address and a 1K Byte Cache. The cache and main memory are divided into blocks where each block is 256 Bytes.
- If direct mapping is used, what is the tag size of each block in cache and how many tag comparisons are made for a one-cache access?
- Repeat part (1) for fully associative mapping.
- Repeat part (1) for 2 way set-associative cache.
- For the direct map find out which of the following accesses are hits and which are misses, addresses are given in Hex, Assume cache is empty initially.
ABC34 7B877 ABC38 7B556 34255 12377 12534
Homework Answers
To overcame the disadvantage of direct mapping and associative mapping, set associative mapping is used. Direct mapping does not requires any replacement algorithm whereas associate and set associative required replacement algorithms like LRU (Least Recent Used).
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Consider a processor that has a 20-bit address and a 1K Byte
Cache. The cache and...
Question 28 7 pts Consider a byte-addressable computer with 24-bit addresses, a cache capable of storing...
Question 28 7 pts Consider a byte-addressable computer with 24-bit addresses, a cache capable of storing a total of 64K bytes of data, and blocks of 32 bytes. If the computer uses direct mapping, the format of the memory address is as follows: bits for the tag field, bits for the cache block number, and bits for the block offset.
Assume the cache can hold 64 kB. Data are transferred between main memory and the cache...
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Let's start with a memory system that is byte addressable and has 14-bit addresses. Now let's...
Let's start with a memory system that is byte addressable and has 14-bit addresses. Now let's add a direct mapped cache that can hold 16 blocks (or has 16 lines) and each block is 4 bytes. The table shoun below details the contents of the cache at a particular point in time. if the valid bit is 1 there is a cache block loaded into the cache with Tag as detailed in the tag column. The columns B0-D3 then show...
Question 33 10 pts For a direct mapped cache of 4 blocks with a cache block...
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Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a...
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) Consider an 8-way associative 64 Kilo Byte cache with 32 byte cache lines. Assume memory addresses are 32 bits long. a). Show how a 32-bit address is used to access the cache (show how many bits for Tag, Index and Byte offset). b). Calculate the total number of bits needed for this cache including tag bits, valid bits and data c). Translate the following addresses (in hex) to cache set number, byte number and tag (i) B2FE3053hex (ii) FFFFA04Ehex...
29 pls clesr ans the average access time for the processor to access an item? 29ns...
29 pls clesr ans
the average access time for the processor to access an item? 29ns Question 29 7 pts Consider a byte-addressable computer with 24-bit addresses, a cache capable of storing a total of 64K bytes of data, and blocks of 32 bytes. If the computer uses direct mapping, the format of the memory address is as follows: bits for the tag field, bits for the cache block number, and bits for the block offset. Question 30 7 pts...
Suppose a computer using direct mapped cache has 232 byte of byte-addressable main memory, and a...
Suppose a computer using direct mapped cache has 232 byte of byte-addressable main memory, and a cache of 1024 blocks, where each cache block contains 32 bytes. a. How many blocks of main memory are there? b. What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag, block, and offset fields? c.To which cache block will the memory address 0x000063FA map?
Question 28 7 pts Consider a byte-addressable computer with 24-bit addresses, a cache capable of storing a total of 64K bytes of data, and blocks of 32 bytes. If the computer uses direct mapping, the format of the memory address is as follows: bits for the tag field, bits for the cache block number, and bits for the block offset.
Let's start with a memory system that is byte addressable and has 14-bit addresses. Now let's add a direct mapped cache that can hold 16 blocks (or has 16 lines) and each block is 4 bytes. The table shoun below details the contents of the cache at a particular point in time. if the valid bit is 1 there is a cache block loaded into the cache with Tag as detailed in the tag column. The columns B0-D3 then show...
Question 33 10 pts For a direct mapped cache of 4 blocks with a cache block size of 1 byte, in which cache block will each memory location map to? The order of accesses if given by the operation number. Indicate if each access is a hit or a miss, and what the tag value is for each entry. Assume that the cache is initially empty, and the accesses are in order of appearance. REDRAW AND COMPLETE THE CACHE TABLE...
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a 32 blocks direct mapped cache. The cache is initially empty. The following decimal memory addresses are referenced 1020, 1006, 1022, 5106, 994, and 2019 Map the addresses to cache blocks and indicate whether hit or miss. Note: You must use the hexadecimal approach in solving this question. You must also show the computations of dividing the memory address into tag bits, cache index bits,...
29 pls clesr ans
the average access time for the processor to access an item? 29ns Question 29 7 pts Consider a byte-addressable computer with 24-bit addresses, a cache capable of storing a total of 64K bytes of data, and blocks of 32 bytes. If the computer uses direct mapping, the format of the memory address is as follows: bits for the tag field, bits for the cache block number, and bits for the block offset. Question 30 7 pts...
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