Question

Can you please help me with these problems:

Gino is planting green beans in his garden. In his experience 60% of the seeds that he plants sprout. Assuming that the events that the plants sprout are independent of each other, what is the probability that no plants sprouts if he plants four seeds?

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Answer 1

1) p = 0.6

P(no plants sprouts out of 4 seeds) = (1 - 0.6)⁴ = 0.0256

2) P(2 cards are of same value) = 13C1 * 4C2 / 52C2 = 13 * 6 / 1326 = 1/17

3) P(2 odd numbers) = P(odd number ) * P(odd number) = (3/6) * (3/6) = 0.25