Solve only ,h , i and j , (1) Consider a so-called Bernoulli equation: y'+p(x)y =...
(1 point) A Bernoulli differential equation is one of the form dy dc + P(x)y= Q(x)y" Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u = yl-n transforms the Bernoulli equation into the linear equation du dr +(1 – n)P(x)u = (1 - nQ(x). Consider the initial value problem xy + y = 3xy’, y(1) = -8. (a) This differential equation can be written in the form (*)...
(1 point) A Bernoulli differential equation is one of the form dete+ P(x)y= Q(2)y". Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u = yl-n transforms the Bernoulli equation into the linear equation am + (1 – n)P(x)u = (1 – n)Q(x). Use an appropriate substitution to solve the equation and find the solution that satisfies y(1) = 1. y(x) =
(15 points) A Bernoulli differential equation is one of the form dy dar + P(x)y= Q(x)y". Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u=yl-n transforms the Bernoulli equation into the linear equation du + (1 - n)P(x) = (1 - nQ(x). dx Use an appropriate substitution to solve the equation xy' +y=2xy? and find the solution that satisfies y(1) = 1.
Problem 5. (1 point) A Bernoulli differential equation is one of the form +P()y= Q()y" (*) Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u =y- transforms the Bemoulli equation into the linear equation + (1 - x)P(3)u = (1 - x)^(x). Consider the initial value problem ry' +y = -3.xy?, y(1) = 2. (a) This differential equation can be written in the form (*) with P(1) =...
A Bernoulli differential equation is one of the form dydx+P(x)y=Q(x)yn. Observe that, if n=0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u=y1−n transforms the Bernoulli equation into the linear equation dudx+(1−n)P(x)u=(1−n)Q(x). Use an appropriate substitution to solve the equation y′−5xy=y5x7, and find the solution that satisfies y(1)=1. y(x)=
An equation in the form with is called a Bernoulli equation and it can be solved using the substitution which transforms the Bernoulli equation into the following first order linear equation for : Given the Bernoulli equation we have so . We obtain the equation . Solving the resulting first order linear equation for we obtain the general solution (with arbitrary constant ) given by Then transforming back into the variables and and using the initial condition to find ....
1 point) An equation in the form y + p(x)y -(x)y with n 0, 1 is called a Bernoulli equation and it can be solved using the substitution wich transforms the Bernoulli equation into the following first order linear equation for v: Given the Bernoulli equation we have n- We obtain the equation u' Solving the resulting first order linear equation for v we obtain the general solution (with arbitrary constant C) given by Then transforming back into the variables...
An equation of the form y'px)ygx)y", a 0,1 is called the Bernoulli equation If we divide by ya we get g(x) . у Чу' + yay' p(x)y-a Next let us make the substitution u y *) (i) Show that y ay' u' [3] = 1-a (ii) By substituting in (*) show that u' + (1— а)p(x)и %3D (1 — а)g(хx) [3] We now have a linear ODE that can be solve for u(x) using an integrating factor. We can then...
Fill in the blanks (1 point) A Bernoulli differential equation is one of the form dy + P()y= Q(Cy" (*) dr Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u=yl-n transforms the Bernoulli equation into the linear equation du dac + (1 - n)P(x)u= (1 - nQ(2). Consider the initial value problem xy' +y= -6xy?, y(1) = -2. (a) This differential equation can be written in the form...
Solve the Bernoulli differential equation. The Bernoulli equation is a well-known nonlinear equation of the form y' + P(x)y = Q(x)yn that can be reduced to a linear form by a substitution. The general solution of a Bernoulli equation is y1 − ne∫(1 − n)P(x) dx = (1 − n)Q(x)e∫(1 − n)P(x) dxdx+C (Enter your solution in the form F(x, y) = C or y = F(x, C) where C is a needed constant.) y8y' − 2y9 = exs