Question

A random sample of 83 individuals shows an average income of $54319 per year. We know...

A random sample of 83 individuals shows an average income of $54319 per year. We know from previous research that the standard deviation for income is 24097. I hypothesis that the true population mean for income is $50337 per year. What is the z-statistic for this hypothesis?

Round your answer to four decimal places.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

60,337 Siven X5,31-50, 337 94,097 Scanned wít Са

Add a comment
Know the answer?
Add Answer to:
A random sample of 83 individuals shows an average income of $54319 per year. We know...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Consider the following random sample observations on stabilized viscosity of asphalt specimens. 2061 2099 1982 1842...

    Consider the following random sample observations on stabilized viscosity of asphalt specimens. 2061 2099 1982 1842 2052 Suppose that for a particular application, it is required that true average viscosity be 2000. Is there evidence this requirement is not satisfied? From previous findings we know that the population standard deviation, σ State the appropriate hypotheses. (Use α-0.05.) 90.8 Ho: μ < 2000 Hai μ 2000 Ho: μ 2000 Ha: μ 2000 Ho: μ 2000 Hai μ-2000 Ho: μ > 2000...

  • A random sample of 107 lightning flashes in a certain region resulted in a sample average...

    A random sample of 107 lightning flashes in a certain region resulted in a sample average radar echo duration of 0.77 sec and a sample standard deviation of 0.50 sec. Calculate a 99% (two-sided) confidence interval for the true average echo duration u. (Round your answers to two decimal places.) sec Interpret the resulting interval. We are 99% confident that the true population mean lies above this interval. We are 99% confident that this interval contains the true population mean....

  • D Question 3 2 pts After collecting a random sample of 101 individuals living in Arizona,...

    D Question 3 2 pts After collecting a random sample of 101 individuals living in Arizona, you find that the average income is $67,886. Using this sample, you determine that the 95% confidence interval for the sample mean is (61 881 73,891). Which of the following statements is correct? There is a 95% chance that the average income for the population of Arizona falls between $61,881 and S73,891 About 95% of the Arizona population have an income between $61,881 and...

  • Hypothesis test for the difference of population means: Z test A study conducted by the research...

    Hypothesis test for the difference of population means: Z test A study conducted by the research department of a pharmaceutical company claims that the annual spending (per person) for prescription drugs for allergy relief, is greater than or equal to the annual spending (per person) for non-prescription allergy relief medicine, Hly. A health insurance company conducted an independent study and collected data from a random sample of 285 individuals for prescription allergy relief medicine. The sample mean is found to...

  • Individuals filing federal income tax returns prior to March 31 received an average refund of $2763...

    Individuals filing federal income tax returns prior to March 31 received an average refund of $2763 Consider the population of “last-minute” filers who mail their tax return during the last five days of the income tax period (typically April 10 to April 15). A researcher suggests that a reason individuals wait until the last five days is that,, on avaerage, these individuals receive lower refunds than do early filers. For a sample of 60 individuals who filed a tax return...

  • According to a research institution, the average hotel price in a certain year was $105.12. Assume...

    According to a research institution, the average hotel price in a certain year was $105.12. Assume the population standard deviation is $20.00 and that a random sample of 32 hotels was selected. Complete parts a through d below. a. Calculate the standard error of the mean. (Round to two decimal places as needed.) b. What is the probability that the sample mean will be less than $106? P(x<$106) (Round to four decimal places as needed.) c. What is the probability...

  • According to a research institution, the average hotel price in a certain year was $100 21...

    According to a research institution, the average hotel price in a certain year was $100 21 Assume the population standard deviation is $17 00 and that a random sample of 4 hotels was selected Complete parts a through d befow a, calculate the standard error of the mean Round to two decimal places as needed ) b. What is the probability that the sample mean will be less than $1027 X < $102) : (Round to four decimal places as...

  • The average income in a certain region in 2013 was $68000 per person per year. Suppose...

    The average income in a certain region in 2013 was $68000 per person per year. Suppose the standard deviation is $33000 and the distribution is​ right-skewed. Suppose we take a random sample of 100 residents of the region. What is the probability that the sample mean will be more than $3300 away from the population​ mean?

  • A random sample of 109 lightning flashes in a certain region resulted in a sample average...

    A random sample of 109 lightning flashes in a certain region resulted in a sample average radar echo duration of 0.82 sec and a sample standard deviation of 0.41 sec. Calculate a 99% (two-sided) confidence interval for the true average echo duration u. (Give answers accurate to 3 decimal places.) (717 923 X) Interpret the resulting interval. o We are 99% confident that this interval does not contain the true population mean. . We are 99% confident that this interval...

  • The data to the right show the average retirement ages for a random sample of workers...

    The data to the right show the average retirement ages for a random sample of workers in Country A and a random sample of workers in Country B. Complete parts a and b Country A 65.2 years 30 Country B 66.8 years 30 Sample mean Sample size Population standard deviation 4.5 years 5.1 years a. Perform a hypothesis test using α= 0.05 to determine if the average retirement age in Country B is higher than it is in Country A....

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT