6. How many atoms of iron are there in a piece of iron thin foil measuring...

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6. How many atoms of iron are there in a piece of iron thin foil measuring 10x9x0.01 cm? Fe Density = 7.8 g/cm3, Atomic weigh

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Answer 1

Answer #1

Size of foil=10×9×0.01 cm

Density = 7.8 g/cm3

atomic weight =55.85 g/g-atom

Avogrado's No.=6.023x 1023 atoms.

$V=10 *9*0.01=0.9 \ cm^3$

$m=density *V=7.8*0.9=7.02 \ gram$

$Mole=\frac{m}{atomic \ weight}=\frac{7.02}{55.85}$

$No.\ of\ atoms\ =Mole * avogrado's No=\frac{7.02}{55.85}*6.023*10^{23}$ $No.\ of\ atoms\ =0.7570*10^{23}$

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Answer 2

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