Brand positioning is process of positioning your brand in minds of customers. It is also referred as positioning strategy.
It is not a short term reputation.
So the given statement is FALSE.
QUESTIONS Match each term Long position in a call option. • Short position in a call option Long position in a put option Short position in a put option • Swap Long position in a futures contract • Short position in a futures contract A Required to purchase the underlying asset at maturity B. Required to sell the underlying asset at maturity C. Has the right but not the obligation to sell whatever is the underlying asset D. Has the...
QUESTION 7 1 po Your firm is short of cash but can borrow from its credit line at an annualized cost of 5%. Further, your firm has just been offered trade credit terms of 2/10 net 30 for purchases made from a supplier How and when should you repay the trade credit obligation? O a on receipt with funds borrowed from the credit line Ob on Day 30 with funds borrowed from the credit line O C on Day 10...
Consider the periodic function defined by 1<t0, 0<t<1, f(t)= f(t+2) f(), and its Fourier series F(t): Σ A, cos(nmi) +ΣB, sin (nπί), F(t)= Ao+ n1 n=1 (a) Sketch the function f(t) the function is even, odd or neither even nor odd. over the range -3<t< 3 and hence state whether (b) Calculate the constant term Ao Consider the periodic function defined by 1
3. (25 Points) Find f(t). f(0) + f(t - 1)f(t)dt = t. Hint: The second term on the left side is a convolution and it might be helpful to use the Laplace Transform. 1 4. (10 Points) Solve the initial value problem by Laplace transform techniques. x" + 5x' + 4x = 0;x(0) = 1,x'(0) = 0. I 5. (15 Points) Find a series solution for the following differential equation. Calculate the radius of convergence. 2(x - 1)y' = 3y...
A particle is moving with acceleration a(t) 36t +16. its position at time t0 is s(0) 12 and its velocity at timet0 is (0)-1. What is its position at time t- 12? Preview A particle is moving with acceleration a(t) 36t +16. its position at time t0 is s(0) 12 and its velocity at timet0 is (0)-1. What is its position at time t- 12? Preview
At time t = 1, a particle is located at position (x, y) = (3, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 9 find its approximate location at time t = 1.04.
Need Help with Practice Exam Short Answer Questions, Differential Equations (1 if (<t<1 3. If fz(t) = { 0 if i<t< 2 -1 if 2 <t<3 f(t) (a) (5 points) Find L(f3(t)) (b) (5 points) If f(t) = f3(t)u(t) = f3(t – 3)u(t – 3) + f3(t – 6)u(t – 6) +... = Po u(t – 3k) f3(t – 3k) find L(F(t)) (c) (5 points) If x" + 5.0' + 6x = f3(t), x(0) = 0, x'(0) = 0 find...
Let Ps have the inner product given by evaluation at -2, -1, 1, and 2. Let po(t)-1. P,()-t, and p20)- a. Compute the orthogonal projection of p2 onto the subspace spanned by Po and P1 b. Find a polynomial q that is orthogonal to Po and p,, such that Po P is an orthogonal basis for Span(Po P1, P2). Scale the polynomial q so that its vector of values at a2(Simplify your answer.) Let Ps have the inner product given...
Suppose the position vector is given by F(t) = (t, t?, +3) Then at time t = 1, the tangential acceleration is 3 16 00 o 22 0 11/14 7 11/14
A bank's largest liability is its shareholder equity. short-term borrowing. deposits of its customers. long-term debt.