At time t = 1, a particle is located at position (x, y) = (3, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 9 find its approximate location at time t = 1.04.
At time t = 1, a particle is located at position (x, y) = (3, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 9 find its approximate location at time t = 1.04.
At time t = 1, a particle is located at position (x,y) = (2, 3). If it moves in the velocity field F(x, y) = (xy - 2, y2 - 12) find its approximate location at time t = 1.05. (x, y) = ( 2.15,2.95 x
At time t = 1, a particle is located at position (x,y) = (3,1). If it moves in the velocity field F(x,y) = <xy - 3, y2 - 9> find its approximate location at time t = 1.02. (x,y) = (_____)
At time t = 1, a particle is located at position (x, y) = (4, 5). If it moves in the velocity field F(x, y) = xy − 3, y2 − 8 find its approximate location at time t = 1.03.
9. A particle moves along the x-axis so that its velocity v at time t, for0 sts 5, is given by v(t) In(t2-3t +3). The particle is at position x 8 at time t 0. a) Find the acceleration of the particle at time t 4. b) Find all times t in the open interval 0<t <5 at which the particle changes direction. During which time intervals, for 0st s 5, does the particle travel to the left? c) Find...
For t ≥ 0, a particle moves along the x-axis. The velocity of the particle at time t is given by v(t)=1+2sin(t^2/2). The particle is at x=2 at time t=4. a)Find position of particle at t=0 b)Find the total distance the particle travels from time t=0 to time t=3
Average and Instantaneous Velocity A particle moves along the x axis. Its position varies with time acording to the expression x =-4t + 2t2, where x is in meters and t is in seconds. The position-time graph for this motion is shown in the figure. Notice that the particle moves in the negative x direction for the first second of motion, is momentarily at rest at the moment t = 1 s, and moves in the positive x direction at times...
A particle moves in the xy plane with constant acceleration. At time t=0 s, the position vector for the particle is r=9.70mx^+4.30my^. The acceleration is given by the vector a=8.00m/s^2x^+3.90m/s^2y^. The velocity vector at time t=o s is v=2.80m/sx^ - 7.00m/sy^. What is the magnitude of the position vector at time t= 2.10 s? What is the angle between the position vector and the positive x-axis at time t= 2.10 s?
Find the work done by the force field F on a particle that moves along the curve C. F(x,y)=xy i+x^2 j C: x=y2 from (0,0) to (4,2) Enter the exact answer as an improper fraction, if necessary. W=
3) A particle moves in the xy-plane with velocity v (m/s) for time t (s) according to u = (6t-4t2)1+ 9). a. Determine the direction of the particle at t 1.5 s in terms of an b. Determine the time or times (for t>0s) when the velocity is zero. If it c. Determine the x-component and y-component of acceleration at d. Determine the time or times (for t>0s) when the acceleration is zero. angle with respect to the x-axis. is...
A particle moves along the x-axis so that its velocity at any time t/geq0 is given by v(t) = 1 - sin(2t). (a) Determine the expression for acceleration at any time t. (b) Find all values t, 0 <t<2, for which the particle is at rest. (c) Determine the expression for the position Jf the particle at any timet if x(0) = 0.