Determine the area under the standard normal curve that lies to the right of the z-score...
Determine the area under the standard normal curve that lies to the right of the z-score 0.11 and to the left of the z-score 0.41. z−0.10.00.10.20.30.40.50.60.70.000.46020.50000.53980.57930.61790.65540.69150.72570.75800.010.45620.50400.54380.58320.62170.65910.69500.72910.76110.020.45220.50800.54780.58710.62550.66280.69850.73240.76420.030.44830.51200.55170.59100.62930.66640.70190.73570.76730.040.44430.51600.55570.59480.63310.67000.70540.73890.77040.050.44040.51990.55960.59870.63680.67360.70880.74220.77340.060.43640.52390.56360.60260.64060.67720.71230.74540.77640.070.43250.52790.56750.60640.64430.68080.71570.74860.77940.080.42860.53190.57140.61030.64800.68440.71900.75170.78230.090.42470.53590.57530.61410.65170.68790.72240.75490.7852 Use the value(s) from the table above.
Homework Answers
solution
P( 0.11< z <0.41 )
= P(z <0.41 ) - P(z <0.11 )
Using z table,
= 0.6591 - 0.5438
answer=0.1153
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