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Determine the area under the standard normal curve that lies to the right of (a) z = -1.47, (b) z= -0.04, (c) z= -1.67, and (

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Sappose We need -1.47 ta N N (0,1) P[z >-147] P[-1.47 22 Lo] + PloL2 LD] Isymmetry POCZ 21.477 + 0.5 r from std Normal tables+)?(27-005] PL-005 c2 co] + Ploc2 Lo] - Ploc 220.05] +0.5 o 0199+ 0.5 0-5199

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