Question

please write step by step so i can follow along. thank you

4) Let (2) = 2* - 202. (a) Use the Closed Interval Method to determine the absolute extrema of S on the interval (0,2). (b) Sketch showing the intercepts on the axes, the local extrema, and concavity the entire graph of f. (5 marks) [10 marks]

Answer 1

firs= 24 2x2 fix) = event. 13° 23°) 2 4 X-Ax = f'(x) siger schome of file) is - +- .. aty=0 So f(x) has to col minimal at x=-1, 12 hocal maxima we have to check on [62] so fol=0 f(0) = -1 The $12) = 8 Se fx hac & absolute minima on (0,2 at . x-1 cmd equal to =-1 - absolute mionima = -1 on (0,2) and absolete maxima = 8 On (0,2) at 2 2 11 x-intercept is = f, ooh le at x=-12, o, da and go intorcept isso be at y=0 cmd local minima az x=-1, I Local modima alt x = 0 for concavity, we find . Graph (c) 7 g(x) = 12 x² - 4 Toy sign Schome of them is tet of f(x) is .. Post * Concave up on (-81 7 / 10 (1) and concave coon on laitos