Question

shift Combustion Analysis -Apply the law of conservation of mass When 2.5000 g of an oxide of mercury, (Hg, 0) is decomposed into the elements by heating, 2.405 g of mercury are produced. Calculate the empirical formula. Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005 g sample of menthol is combusted, producing 0.2829 g of CO, and 0.1159 g of H,O. What is the empirical formula for menthol?

please solve these 2. Step by step and explain please! so i can follow along.
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Answer 1

2.4o5 Kloo = 96.27. % Hg = 205 0 = 100 - % of Hg = 3.8 4g 3.8 96.2 atome naus divide witt 3.8 -0.24 962 = 0.48) 76 divide with small number 0.24 = ti 0.48 22 0.24 = 1 formula is HgO. Oozu in emperical 12 x 0.2829x100 mass of co2 x100= nu ooloos 7. (= nu a mais of cone - 76.77. x 0.1159 x100 - 12.847 0.1005 40=100(%. C + 6H) = 10.57. ç Pos 7607 128 10.5 76.7 6.3 128 - 12.8 1038 = 0.66 12.8 0.66 O 0.66 3.66 -19 0.66 = 1 multiply with "2" amperical torule is G9H3802.