Question

Problem 3 (26 points). Use the Direct Displacement Method to compute all support reactions for the structure in Figure 2. Note that this structure is identical to that in Figure 1 except that A is a pinned support rather than a roller. You may make use of any computations from Problem 1 that are useful without redoing them! El is constant. 6 ft 6 ft 6ft 20 kips 14kips 8 kips B Figure 2 2 kips/ft 12ft.

work from #1

Answer 1

18 kips ,20kips 114 Kips NIB fighoreo 19 Gjy toe of it to دی Nous applying Equilibrium ego for statelo * E(For te versiele = EFV=0 > RCV = 8+20 +14 = 42 kips * Efna = 0 RAM » Ram Reh. se * Moment) &c=0 . RAH12 + 14 x 6 = 8x12 +20 6+2410 >RAH = 13 kips! Rela 23 Kips Now fighure ☺: rips OK ,20 kips Ķ kips kips Rru Rev V 2016 VN 1242 -24 LARAN Now :-- ** 3 Fv=0 > RAV+Rev = 8+20+14 = 42 ** ZFH 20 > 24 +RCH = RAH - >0 - 0 NIRA → RAH-RCH = 24-0

** EMEC =0 Cacau 1 -w (+) > RAH 24x6+8x12 +20x6 = Rav x/2 + RAHX 24 +1486 → RAV x 12 + RAH X 24 = 276 cm | RAM + 2 AH = 330) * Number of unknown = (RAMIRAN GRCH , Rey)= 4 * EMEA CO Aca 6) → Rev x 12 = RcHX12 +14448 + 2046 +2446 → Rev - RcH = 43 - Do now from een oo -RCH - RAV = 1~ © een ☺ + ego -RAV-RAH - RAM +BCH = 1724 7 - RAN -RAH = -23 » RAV +RAH = 23 0 mee? - een → RAH = 0) -RCH 2-24 →RAV = 23 Prev 342-23 =191 Raid = 0