Question

A 50 kg diver in a full layout position, with a total body radius of gyration with respect to her transverse prinicpal axis equal to 0.45 m, leaves a springboard with an angular velocity of 6 rad/s. What is the diver's angular velocity when she assumes a tuck position, reducing her radius of gyration to 0.25 m?

Answer 1

find H when driver leaves the board

H = m k² w

= (50 kg) (0.45 m)² (6 rad/s)

= 60.75 kg.m2/s

H is constant, find w when k is reduced to 0.25 m

60.75 kg.m2/s = (50 kg) (0.25)² w

w = 19.44 rad/s