Question

The equilibrium constant, K_c, for the following reaction is 6.50×10^-3 at 298K.

2NOBr(g)<====> 2NO(g) + Br₂(g)

If an equilibrium mixture of the three gases in a 16.4 L container at 298K contains 0.383 mol of NOBr(g) and 0.230 mol of NO, the equilibrium concentration of Br₂ is____M

The equilibrium constant, K_c , for the following reaction is 7.00×10^-5 at 673 K.

NH₄I(s) <====>NH₃(g) + HI(g)

If an equilibrium mixture of the three compounds in a 5.04 L container at 673 K contains 2.25 mol of NH₄I(s) and 0.339 mol of NH₃, the number of moles of HI present is _____M

Consider the following reaction:

2NOBr(g) <=======>2NO(g) + Br₂(g)

If 0.325 moles of NOBr(g), 0.405 moles of NO, and 0.613 moles of Br₂ are at equilibrium in a 15.0 L container at 531 K, the value of the equilibrium constant, K_c, is ____m

Answer 1

1.

The given reaction is

For a generic reaction , the equilibrium constant Kc is expressed as

Where the concentrations are equilibrium values.

Hence, for our reaction, the expression of Kc can be written as

It is given that volume of the container = 16.4 L

We can calculate the equilibrium concentration of given species from their number of moles as follows:

Hence, putting in the values in equilibrium expression, we can calculate the equilibrium concentration of Br₂.

Hence, the equilibrium concentration of Br₂ is 0.0180 M approximately. (Rounded to three significant figures).

2.

The given equilibrium is

The equilibrium constant Kc of the reaction can be written as

Note that NH₄I is a solid and its concentration is taken as unity. Hence, it does not appear in the equilibrium constant expression.

Volume of the container = 5.04 L

Hence, we can calculate the concentration of NH₃ at equilibrium as follows:

Hence, we can calculate the concentration of HI as follows:

Hence, the number of moles of HI can be calculated as

Hence, the number of moles of HI present is ( Rounded to three significant figures).

3.

The given reaction is

The equilibrium expression can be written as

Volume of the container = 15.0 L

Hence, we can calculate the concentrations at equilibrium from the number of moles as follows;

Now, we can calculate the equilibrium constant Kc as follows:

Hence, the value of equilibrium constant Kc is . (Rounded to three significant figures).