Solution :
=> Option a. minimum: 807.78 ; maximum: 859.42
Given that n = 1042 , p = 0.80
=> q = 1 - p = 0.20
=> mean μ = n*p = 1042*0.80 = 833.6
=> Standard deviation σ = sqrt(n*p*q) = sqrt(1042*0.80*0.20) = 12.91
=> Minimum = μ - 2*σ
= 833.6 - 2*12.91
= 807.78
=> Maximum = μ + 2*σ
= 833.6 + 2*12.91
= 859.42
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