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explain why there are no integers x and y such that 25x+30y=1
Copy of R - 25x<2, -2sys 2 Consider the functions f(x,y)= 3 - 3 xy - x - y and the region (Then during the investigation of Absolute Extrema, we have to investigate(chose all possible options for values at all four intersection points to Investigate for Internal critical points and (-1,-1) is an internal critical point lla for Internal critical points and (1,1) is an internal critical point.Illa for critical points on four boundary.IVO critical points on three boundary VO
Question 5: Consider the piecewise function 13x1 if x1 8(1) = 2 If x=1 2x 5 ifkX 12 Marks] b. Determine lim g(x). [2 Marks] c. Determine lim 8(x). X 12. Marks] d. Is 8(x) continuous at x = -1? Why or why not?
Evaluate: vr y-x dA , y + 2x+1 where R is the parallelogram bounded by y-x-2, y-x-3, y + 2x = 0, andy+2x=4. Evaluate: vr y-x dA , y + 2x+1 where R is the parallelogram bounded by y-x-2, y-x-3, y + 2x = 0, andy+2x=4.
a - e (a) X + y +z = 11 X – Y – 2= -3 -2 + y - 2 = 5 (3x – y + 2z = 2 (b) x+y+z+t+p=17 X - Y - 2-t-p= -5 z +t+ p + y = 11 p - x - y = 1 -t + x = 10 (c) x +y + 2+t= -6 X - Y - 2 -t = 20 y - X=-39 2x + 3t + y -...
1. Find Derivative: y=2x^3 ln(2x^3+7) a. y' = 36x^4 ÷ 2x^3+7 b. y'=12x^5 ÷ 2x^3+7 - 6x^2 ln (2x^3+7) c. y' = -36x^4 ÷ 2x^3 +7 d. y'=12x^5 ÷ 2x^3+7 + 6x^2 ln (2x^3+7) e. y'=2x^3 ÷ 2x^3+7 - 6x^2 ln (2x^3+7) f. 2x^3 ÷ 2x^3+7 + 6x^2 ln (2x^3+7) 2. Find exact value of the expression. Sin(arctan(x/4)) a. √16-x^2 ÷ x. b. x ÷√16-x^2. c. undefined. d. √16+x^2 ÷ x. e. 4 ÷ √16-x^2 f.none
Let X be a continuous random variable whose probability density function is fax) (2x +af (0 1) if x E (0; 1) f (x) - ind 1) the coefficient a; 2) P(0.5<X<0.7); 3) P(X 3) Part 3 sample of measurements is given XI-8 -210|2|8 Y 8 4 2 2 0
(1 point) Find y as a function of x if y(x) = -2sin(2x)+7cos(2x)+8
using the general power rule Question 1 let y = (x2 +x)3 Find y' 2x+1 3(x2+x)2 3(x2+x)2 (2x+1) • (x2+x)2 (2x+1) recall general power rule formula has three parts: [u(x)" ]' = n u(x)" 1 u'(x) Question 2 let y = (x3 +x2) 1/3 Find y' (x3 +x2) 1/3 (1/3) (x3 +x2) 1/3 . (1/3)(x3 +x2)-2/3 (1/3)(x3 +x2-2/3 (3x2+2x) recall general power rule has three parts. [u(x)"l' = n u(x)n-1 u'(x) Question 5 let g(x) = 1/(x3+x2)3 find g'(x) (x²+x23...
For X and Y with the initial joint density of f(x, y) = 3/2(2 − 2x − y), 0 < x < 1 and 0 < y < 2 − 2x, find P(Y < 1|X = 1/2 ).