Let f(x) = 2x4 +x4cos(1/x) for x ̸= 0 and f(0) = 0. Show that 0...

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Let f(x) = 2x4 +x4cos(1/x) for x ̸= 0 and f(0) = 0.

Show that 0 is a global minimum x for f but for every neighbourhood V of 0 there exists x,y ∈ V such that f′(x) > 0 and f′(y) < 0.

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Answer #1

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Answer 2

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