What is the age in years of a bone in which the 14C/12C ratio is measured to be 3.9×10−13?
t = -(t1/2/ln(2)) * ln(xt/x0)
t1/2 = half life of 14-C = 5730 yrs.
xt/x0 = 3.9*10^(-13)
t = -(5730/ln2)*ln(3.9*10^(-13))
= 236199.7 years
What is the age in years of a bone in which the 14C/12C ratio is measured...
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