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For what value( or values) of n does an n-sided polygon have 11 times as many...

For what value( or values) of n does an n-sided polygon have 11 times as many diagonals as sides?

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Answer #1

formula number of diagnols for n-sided polygon = n(n-3) condition Il times as many diagnola as sidea. > II.N = n(n-3) >n : pe

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