Question

A Revi Use molar volume to calculate each of the following at STP: Part A the volume, in liters, occupied by 3.50 moles of N2 gas 190 AS O O ? V = Submit Request Answer Part B the number of moles of CO2 in 2.10 L of CO2 gas Co Agon O O ? V = mol Submit Request Answer

Answer 1

1 mol = 22.4L at STP.

Part A: mole = 3.5 moles

Volume = 3.5 X 22.4 = 78.4 L N2 gas.

​​​​​​Part B: Volume = 2.1 L

Mole = 2.1 / 22.4 = 9.375 X 10^(-2) = 0.09375 mol

(3.38). Heat, Q = mC(dT) ; where m = mass in g, C = specific heat and dT = change in temperature.

Part A: m = 95g, Ti = 45°C, Tf = 29°C and C = 1 cal/g-°C.

Heat lost = -95 X 1 X (29-45) = 1520 cal.

Part B: m = 21g, Ti = 86°C, Tf = 62°C and C = 4.184 J/g-°C.

Heat Lost = -21 X 4.184 X (62 - 86) = 2108.74 J

Part C: m = 4.8 kg, Ti = 22°C and Tf = 24°C.

Heat = 4.8 X 1 X (24-22) = 9.6 kCal.

Part D: m = 225g = 0.225 kg, Ti = 18°C and Tf = 175°C

Heat = 0.225 X 4.184 X (175-18) = 147.8 kJ.