a )
given
east west direction 140 m
and north south direction 120 m
now
r1 = 3 X 120 = 360 j
r2 = 4 X 140 = 560 i
r3 = 4 X 120 = 480 j
r4 = 1 X 140 = 140 i
along east direction the displacement is = 560 + 140 = 700 i m
along north direction the displacement is = 360 + 480 = 840 j m
the magnitude is = ( 7002 + 8402 )1/2
= 1093.44 m
b )
the direction is
= tan-1 ( 700 / 840 )
= 39.8o N of E
3.1 - Vector Addition and Subtraction: Graphical Methods The figure below shows the path (red arrows)...
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