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Consta Part A Determine the magnitude of the force on an electron traveling 6.15x109 m/s horizontally to the east in a vertic
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Answer #1

Solution velocity = Ve = 6:15 X10 x 10 m/s B=0.55T force on electron QUBSino here o=90° = f -14 O & f =18x10 19x6:15 x 10 xoo

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