A. Determine the magnitude of the force on an electron traveling 5.40×105 m/s horizontally to the...
A. Determine the magnitude of the force on an electron traveling 5.40×105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.33 T .
B. Determine the direction of the force on an electron.
Homework Answers
a)
here
Fmax = q * v * B
Fmax = 1.6 * 10^-19 * 5.4 * 10^5 * 0.33
Fmax = 2.85 * 10^-14 N
b)
by the right hand rule the force must be directed to the north
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how do i know this???
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F= -e v B i <-----why i is positive when in the diagram above
k x j = -i ???
F= -1.6 x 10-19 x...
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