Determine the magnitude of the force on an electron traveling 5.95×105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.28 T
F= BVq,
B= 0.28T
V= 5..95x10^5 m/s
q= 1.6x10^(-19)C (constant)
F= 0.28*5.95*10^5*1.6*10^-19
F= 2.665*10^-14 N
By the right hand rule, the force must be directed to the North .
Determine the magnitude of the force on an electron traveling 5.95×105 m/s horizontally to the east...
Determine the magnitude of the force on an electron traveling 6.05×105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.35 T . Determine the direction of the force on an electron.
Determine the magnitude of the force on an electron traveling 7.20×105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.59 T .
Determine the magnitude of the force on an electron traveling 6.15×105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.80 T . Which Direction ?
A. Determine the magnitude of the force on an electron traveling 5.40×105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.33 T . B. Determine the direction of the force on an electron.
Determine the magnitude of the force on an electron traveling 6.45-105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.70 Express your answer to two significant figures and include the appropriate units. JA → ? F Value N Submit Request Answer Part B Determine the direction of the force on an electron. O to the North to the South O to the East O to the West Submit Request Answer
Determine the magnitude of the force on an electron traveling 8.31E+5 m/s horizontally to the east in a vertically upward magnetic field of strength 0.800 T. (in N) A: 2.79
Determine the magnitude and direction of the force on an electron traveling 8.75x105 m/s horizontally to the east in a vertically upward magnetic field of strength 0.75 T.
A) Determine the magnitude of the force on an electron traveling 6.35×10^5 m/s horizontally to the east in a vertically upward magnetic field of strength 0.75 T.B) Determine the direction of the force on an electron. 1. to the North 2. to the South 3. to the East 4. to the West
Consta Part A Determine the magnitude of the force on an electron traveling 6.15x109 m/s horizontally to the east in a vertically upward magnetic field of strength 0.55 T. Express your answer to two significant figures and include the appropriate units. NA ? Fmax = Value N Submit Request Answer - Part B Determine the direction of the force on an electron to the North to the South O to the East O to the West Submit Request Answer ovide...
Determine the magnitude and direction of the force on an electron traveling 8.75 x 105m/s horizontally to the east in a vertically upward magnetic field of strength 0.45 T. I got that v= v j <----vector and B= B k <----vector, but how do i know this??? The answer is F= (-e) v x B F= -e v B i <-----why i is positive when in the diagram above k x j = -i ??? F= -1.6 x 10-19 x...