0.0411 mol of glucose in 85.2 mL of solution using 3 sig figs Thank you

Question

Question

0.0411 mol of glucose in 85.2 mL of solution using 3 sig figs

Thank you

Answer 1

Answer #1

Answer : Hnece the molarity of glucose = 0.0411 * 1000/85.2 = 0.482 M

hence molarity in 3 sig = 0.482 M

Answer 2

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